7x^2+158x-69=0

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Solution for 7x^2+158x-69=0 equation:



7x^2+158x-69=0
a = 7; b = 158; c = -69;
Δ = b2-4ac
Δ = 1582-4·7·(-69)
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(158)-164}{2*7}=\frac{-322}{14} =-23 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(158)+164}{2*7}=\frac{6}{14} =3/7 $

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